What is the d/(dy)((x)(y^2cos(x))) ?

The d/(dy)((x)(y^2cos(x))) is 2xycos(x)

What is the first d/(dy)((x)(y^2cos(x))) ?

The first d/(dy)((x)(y^2cos(x))) is 2xycos(x)

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\frac{d}{d y} ((x) (y^{2} cos (x)))

2 x y cos (x)

Solution steps

\frac{d}{d y} ((x) (y^{2} cos (x)))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x cos (x) \frac{d}{d y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x cos (x) \cdot 2 y^{2 - 1}

Simplify

= 2 x y cos (x)

[(x - 2 y) + 7] [(x - 2 y) - 7]

(x - 2) (2 - 1)

3 cos (600 t) - 5 cos (600 t + 110)

(a + b) 2 - (c + d)^{2}

4 e^{j^{2} t} + 4 j e^{j^{2} t}

What is the d/(dy)((x)(y^2cos(x))) ?
The d/(dy)((x)(y^2cos(x))) is 2xycos(x)
What is the first d/(dy)((x)(y^2cos(x))) ?
The first d/(dy)((x)(y^2cos(x))) is 2xycos(x)