What is factor 4e^{j^2t}+4je^{j^2t} ?

The solution to factor 4e^{j^2t}+4je^{j^2t} is 4e^{j^2t}(1+j)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 4e^{j^2t}+4je^{j^2t}

factor

4 e^{j^{2} t} + 4 j e^{j^{2} t}

4 e^{j^{2} t} (1 + j)

Solution steps

4 e^{j^{2} t} + 4 j e^{j^{2} t}

Rewrite as

= 1 \cdot 4 e^{j^{2} t} + 4 e^{j^{2} t} j

Factor out common term

4 e^{j^{2} t}

= 4 e^{j^{2} t} (1 + j)

I m [π]

π r^{2} + π r l

(d t)^{2}

5 cos (t) + 5 sin (t) d t

- 8 y^{2} e^{2 x} + 4 y e^{3 x}

What is factor 4e^{j^2t}+4je^{j^2t} ?
The solution to factor 4e^{j^2t}+4je^{j^2t} is 4e^{j^2t}(1+j)