What are the solutions to the equation x^2+16x+7=0 ?

The solutions to the equation x^2+16x+7=0 are x=-8+sqrt(57),x=-8-sqrt(57)

Find the zeros of x^2+16x+7=0

The zeros of x^2+16x+7=0 are x=-8+sqrt(57),x=-8-sqrt(57)

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x^{2} + 16 x + 7 = 0

x = - 8 + 57, x = - 8 - 57

Solution steps

x^{2} + 16 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 7 = 257

x_{1, 2} = \frac{- 16 \pm 2 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 57}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 57}{2 \cdot 1}

x = \frac{- 16 + 2 57}{2 \cdot 1} : - 8 + 57

x = \frac{- 16 - 2 57}{2 \cdot 1} : - 8 - 57

The solutions to the quadratic equation are:

x = - 8 + 57, x = - 8 - 57

\frac{- 2 - 6 i}{- 1 - 3 i}

27 x^{6} - 64 y^{6}

x - 5 = 1

1 (- 4.94 b - 19.24) = - 4 b - 28.64

\frac{x}{2} = - 6

What are the solutions to the equation x^2+16x+7=0 ?
The solutions to the equation x^2+16x+7=0 are x=-8+sqrt(57),x=-8-sqrt(57)
Find the zeros of x^2+16x+7=0
The zeros of x^2+16x+7=0 are x=-8+sqrt(57),x=-8-sqrt(57)