What is ((3m^{-2}n)^{-3})/(6mn^{-2)} ?

The solution to ((3m^{-2}n)^{-3})/(6mn^{-2)} is (m^5)/(162n)

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simplify ((3m^{-2}n)^{-3})/(6mn^{-2)}

simplify

\frac{( 3 m ^{- 2} n ) ^{- 3}}{6 m n ^{- 2}}

\frac{m ^{5}}{162 n}

Solution steps

\frac{( 3 m ^{- 2} n ) ^{- 3}}{6 m n ^{- 2}}

Simplify

(3 m^{- 2} n)^{- 3} : 3^{- 3} m^{6} n^{- 3}

= \frac{3 ^{- 3} m ^{6} n ^{- 3}}{6 m n ^{- 2}}

Factor the number:

6 = 3 \cdot 2

= \frac{3 ^{- 3} m ^{6} n ^{- 3}}{3 \cdot 2 m n ^{- 2}}

\frac{3 ^{- 3}}{3} = \frac{1}{3 ^{4}}

= \frac{m ^{6} n ^{- 3}}{3 ^{4} \cdot 2 m n ^{- 2}}

Simplify

\frac{m ^{6}}{m} : m^{5}

= \frac{m ^{5} n ^{- 3}}{3 ^{4} \cdot 2 n ^{- 2}}

Simplify

\frac{n ^{- 3}}{n ^{- 2}} : \frac{1}{n}

= \frac{m ^{5}}{3 ^{4} \cdot 2 n}

Simplify

3^{4} \cdot 2 n : 162 n

= \frac{m ^{5}}{162 n}

12 x + 8 y

\frac{\frac{5}{11}}{1 - \frac{5}{11}}

9 x^{2} - \frac{243 x}{10} + \frac{9}{2} = 0

a^{3} + a^{2}

(x - 1) (x - 2) = 0

What is ((3m^{-2}n)^{-3})/(6mn^{-2)} ?
The solution to ((3m^{-2}n)^{-3})/(6mn^{-2)} is (m^5)/(162n)