What are the solutions to the equation 2(x-7)^2=32 ?

The solutions to the equation 2(x-7)^2=32 are x=11,x=3

Find the zeros of 2(x-7)^2=32

The zeros of 2(x-7)^2=32 are x=11,x=3

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2 (x - 7)^{2} = 32

x = 11, x = 3

Solution steps

2 (x - 7)^{2} = 32

Divide both sides by

2

(x - 7)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 16 : x = 11

Solve

x - 7 = - 16 : x = 3

The solutions to the quadratic equation are:

x = 11, x = 3

(22 x^{\frac{1}{2}})^{2}

\frac{1.75 \cdot 56 + 0}{1.75 + 1}

4 n^{2} + 16 n + 15

625 \geq 5^{a + 8}

3 (x + 5) + x (x + 5)

What are the solutions to the equation 2(x-7)^2=32 ?
The solutions to the equation 2(x-7)^2=32 are x=11,x=3
Find the zeros of 2(x-7)^2=32
The zeros of 2(x-7)^2=32 are x=11,x=3