What is factor 18x^2+41x-10 ?

The solution to factor 18x^2+41x-10 is (9x-2)(2x+5)

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factor 18x^2+41x-10

factor

18 x^{2} + 41 x - 10

(9 x - 2) (2 x + 5)

Solution steps

18 x^{2} + 41 x - 10

Break the expression into groups

= (18 x^{2} - 4 x) + (45 x - 10)

Factor out

2 x

from

18 x^{2} - 4 x : 2 x (9 x - 2)

Factor out

5

from

45 x - 10 : 5 (9 x - 2)

= 2 x (9 x - 2) + 5 (9 x - 2)

Factor out common term

9 x - 2

= (9 x - 2) (2 x + 5)

\frac{4 !}{4 ! ( 4 - 4 ) !}

4 a^{3} + 8 a

u^{2} - 18 u + 81

2 (- \frac{1}{5})^{0}

3 x^{2} + 9 x + 6 = 0

What is factor 18x^2+41x-10 ?
The solution to factor 18x^2+41x-10 is (9x-2)(2x+5)