What are the solutions to the equation 3x^2+9x+6=0 ?

The solutions to the equation 3x^2+9x+6=0 are x=-1,x=-2

Find the zeros of 3x^2+9x+6=0

The zeros of 3x^2+9x+6=0 are x=-1,x=-2

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3 x^{2} + 9 x + 6 = 0

x = - 1, x = - 2

Solution steps

3 x^{2} + 9 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 6 = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 \cdot 3}, x_{2} = \frac{- 9 - 3}{2 \cdot 3}

x = \frac{- 9 + 3}{2 \cdot 3} : - 1

x = \frac{- 9 - 3}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

ln (4) r^{2} = 3

\frac{15 !}{( 15 - 4 ) !}

2 + \frac{a}{4} = - 1

\frac{20 x ^{2} y ^{5}}{12 x y ^{7}}

\frac{3 x + 16}{5} = 2

What are the solutions to the equation 3x^2+9x+6=0 ?
The solutions to the equation 3x^2+9x+6=0 are x=-1,x=-2
Find the zeros of 3x^2+9x+6=0
The zeros of 3x^2+9x+6=0 are x=-1,x=-2