What are the solutions to the equation ln(4)r^2=3 ?

The solutions to the equation ln(4)r^2=3 are r=sqrt(3/(2ln(2))),r=-sqrt(3/(2ln(2)))

Find the zeros of ln(4)r^2=3

The zeros of ln(4)r^2=3 are r=sqrt(3/(2ln(2))),r=-sqrt(3/(2ln(2)))

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ln (4) r^{2} = 3

r = \frac{3}{2 ln ( 2 )}, r = - \frac{3}{2 ln ( 2 )}

Solution steps

ln (4) r^{2} = 3

Simplify

ln (4) : 2 ln (2)

2 ln (2) r^{2} = 3

Divide both sides by

2 ln (2)

r^{2} = \frac{3}{2 ln ( 2 )}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{3}{2 ln ( 2 )}, r = - \frac{3}{2 ln ( 2 )}

\frac{15 !}{( 15 - 4 ) !}

2 + \frac{a}{4} = - 1

\frac{20 x ^{2} y ^{5}}{12 x y ^{7}}

\frac{3 x + 16}{5} = 2

(1 - y^{2}) = 0

What are the solutions to the equation ln(4)r^2=3 ?
The solutions to the equation ln(4)r^2=3 are r=sqrt(3/(2ln(2))),r=-sqrt(3/(2ln(2)))
Find the zeros of ln(4)r^2=3
The zeros of ln(4)r^2=3 are r=sqrt(3/(2ln(2))),r=-sqrt(3/(2ln(2)))