What is 8<=-3(4x+1)<= 24 ?

The solution to 8<=-3(4x+1)<= 24 is -9/4 <= x<=-11/12

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8<=-3(4x+1)<= 24

8 \leq - 3 (4 x + 1) \leq 24

- \frac{9}{4} \leq x \leq - \frac{11}{12}

Solution steps

8 \leq - 3 (4 x + 1) \leq 24

a \leq u \leq b

then

a \leq u and u \leq b

8 \leq - 3 (4 x + 1) and - 3 (4 x + 1) \leq 24

8 \leq - 3 (4 x + 1) : x \leq - \frac{11}{12}

- 3 (4 x + 1) \leq 24 : x \geq - \frac{9}{4}

Combine the intervals

x \leq - \frac{11}{12} and x \geq - \frac{9}{4}

Merge Overlapping Intervals

- \frac{9}{4} \leq x \leq - \frac{11}{12}

0.4 \cdot 2

lo g_{7} (1) = x

t^{2} - 7 t - 30

0.15 x \leq 5

y^{3} - 7 y^{2} + y - 7

What is 8<=-3(4x+1)<= 24 ?
The solution to 8<=-3(4x+1)<= 24 is -9/4 <= x<=-11/12