What are the solutions to the equation 3(x^2+2)-8=1 ?

The solutions to the equation 3(x^2+2)-8=1 are x=1,x=-1

Find the zeros of 3(x^2+2)-8=1

The zeros of 3(x^2+2)-8=1 are x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x^{2} + 2) - 8 = 1

x = 1, x = - 1

Solution steps

3 (x^{2} + 2) - 8 = 1

Move

8

to the right side

3 (x^{2} + 2) = 9

Divide both sides by

3

x^{2} + 2 = 3

Move

2

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(\frac{6}{3})^{2}

- 6 \cdot \frac{7}{3}

4^{\frac{1}{2}}

\frac{25}{5}

x^{2} - 7 x = - 13

What are the solutions to the equation 3(x^2+2)-8=1 ?
The solutions to the equation 3(x^2+2)-8=1 are x=1,x=-1
Find the zeros of 3(x^2+2)-8=1
The zeros of 3(x^2+2)-8=1 are x=1,x=-1