What is factor 2cos^2(θ)-7cos(θ)+3 ?

The solution to factor 2cos^2(θ)-7cos(θ)+3 is (2cos(θ)-1)(cos(θ)-3)

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factor 2cos^2(θ)-7cos(θ)+3

factor

2 cos^{2} (θ) - 7 cos (θ) + 3

(2 cos (θ) - 1) (cos (θ) - 3)

Solution steps

2 cos^{2} (θ) - 7 cos (θ) + 3

Break the expression into groups

= (2 cos^{2} (θ) - cos (θ)) + (- 6 cos (θ) + 3)

Factor out

cos (θ)

from

2 cos^{2} (θ) - cos (θ) : cos (θ) (2 cos (θ) - 1)

Factor out

- 3

from

- 6 cos (θ) + 3 : - 3 (2 cos (θ) - 1)

= cos (θ) (2 cos (θ) - 1) - 3 (2 cos (θ) - 1)

Factor out common term

2 cos (θ) - 1

= (2 cos (θ) - 1) (cos (θ) - 3)

x^{2} - \frac{61}{26} x - 1

a e^{b} x + c

\frac{d}{d t} ((z (t)) (t^{3}))

3 (ln (3))

(ln (x)) (2 x cos (x^{2}))

What is factor 2cos^2(θ)-7cos(θ)+3 ?
The solution to factor 2cos^2(θ)-7cos(θ)+3 is (2cos(θ)-1)(cos(θ)-3)