What are the solutions to the equation (8x+7)(x+1)=9 ?

The solutions to the equation (8x+7)(x+1)=9 are x= 1/8 ,x=-2

Find the zeros of (8x+7)(x+1)=9

The zeros of (8x+7)(x+1)=9 are x= 1/8 ,x=-2

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(8 x + 7) (x + 1) = 9

x = \frac{1}{8}, x = - 2

Solution steps

(8 x + 7) (x + 1) = 9

Expand

(8 x + 7) (x + 1) : 8 x^{2} + 15 x + 7

8 x^{2} + 15 x + 7 = 9

Move

9

to the left side

8 x^{2} + 15 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 8 ( - 2 )}{2 \cdot 8}

1 5^{2} - 4 \cdot 8 (- 2) = 17

x_{1, 2} = \frac{- 15 \pm 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 15 + 17}{2 \cdot 8}, x_{2} = \frac{- 15 - 17}{2 \cdot 8}

x = \frac{- 15 + 17}{2 \cdot 8} : \frac{1}{8}

x = \frac{- 15 - 17}{2 \cdot 8} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{8}, x = - 2

6 x^{2} - 17 x + 13 = 20 x^{2} - 32

∣ 1 - 4 x ∣ - 11 < - 8

3 (x + 8)^{2} = 3

(- 7 p)^{3}

8 a^{3} - 125 b^{3}

What are the solutions to the equation (8x+7)(x+1)=9 ?
The solutions to the equation (8x+7)(x+1)=9 are x= 1/8 ,x=-2
Find the zeros of (8x+7)(x+1)=9
The zeros of (8x+7)(x+1)=9 are x= 1/8 ,x=-2