What are the solutions to the equation 6x^2-17x+13=20x^2-32 ?

The solutions to the equation 6x^2-17x+13=20x^2-32 are x=-5/2 ,x= 9/7

Find the zeros of 6x^2-17x+13=20x^2-32

The zeros of 6x^2-17x+13=20x^2-32 are x=-5/2 ,x= 9/7

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6 x^{2} - 17 x + 13 = 20 x^{2} - 32

x = - \frac{5}{2}, x = \frac{9}{7}

Decimal Notation

x = - 2.5, x = 1.28571 \dots

Solution steps

6 x^{2} - 17 x + 13 = 20 x^{2} - 32

Move

32

to the left side

6 x^{2} - 17 x + 45 = 20 x^{2}

Move

20 x^{2}

to the left side

- 14 x^{2} - 17 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 ( - 14 ) \cdot 45}{2 ( - 14 )}

(- 17)^{2} - 4 (- 14) \cdot 45 = 53

x_{1, 2} = \frac{- ( - 17 ) \pm 53}{2 ( - 14 )}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 53}{2 ( - 14 )}, x_{2} = \frac{- ( - 17 ) - 53}{2 ( - 14 )}

x = \frac{- ( - 17 ) + 53}{2 ( - 14 )} : - \frac{5}{2}

x = \frac{- ( - 17 ) - 53}{2 ( - 14 )} : \frac{9}{7}

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = \frac{9}{7}

∣ 1 - 4 x ∣ - 11 < - 8

3 (x + 8)^{2} = 3

(- 7 p)^{3}

8 a^{3} - 125 b^{3}

23 + 42

What are the solutions to the equation 6x^2-17x+13=20x^2-32 ?
The solutions to the equation 6x^2-17x+13=20x^2-32 are x=-5/2 ,x= 9/7
Find the zeros of 6x^2-17x+13=20x^2-32
The zeros of 6x^2-17x+13=20x^2-32 are x=-5/2 ,x= 9/7