What is factor (x^2-4x)-16 ?

The solution to factor (x^2-4x)-16 is (x-2(1+sqrt(5)))(x+2(sqrt(5)-1))

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factor (x^2-4x)-16

factor

(x^{2} - 4 x) - 16

(x - 2 (1 + 5)) (x + 2 (5 - 1))

Solution steps

(x^{2} - 4 x) - 16

Remove parentheses:

(a) = a

= x^{2} - 4 x - 16

Solve

x^{2} - 4 x - 16 = 0 : x = 2 (1 + 5), x = 2 (1 - 5)

Polynom can therefore be factored into

= (x - (2 (1 + 5))) (x - (2 (1 - 5)))

Refine

= (x - 2 (1 + 5)) (x - 2 (1 - 5))

Factor

1 - 5 : - (5 - 1)

= (x - 2 (1 + 5)) (x - (- 2 (5 - 1)))

Apply rule

- (- a) = a

= (x - 2 (1 + 5)) (x + 2 (5 - 1))

ab + b^{2} - a c - b c

- 2 A + (- 1.5) B + C + 1.5 D

4 (\frac{1}{2})^{2}

e^{4 t} sin (h) (5 t)

\frac{d}{d c} ((t) (c e^{r (t, c) t}))

What is factor (x^2-4x)-16 ?
The solution to factor (x^2-4x)-16 is (x-2(1+sqrt(5)))(x+2(sqrt(5)-1))