What is factor (2x+3)/(4x^2-9) ?

The solution to factor (2x+3)/(4x^2-9) is 1/(2x-3)

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factor (2x+3)/(4x^2-9)

factor

\frac{2 x + 3}{4 x ^{2} - 9}

\frac{1}{2 x - 3}

Solution steps

\frac{2 x + 3}{4 x ^{2} - 9}

Factor

4 x^{2} - 9 : (2 x + 3) (2 x - 3)

= \frac{2 x + 3}{( 2 x + 3 ) ( 2 x - 3 )}

Cancel the common factor:

2 x + 3

= \frac{1}{2 x - 3}

m^{75} - 125

\frac{d}{d x} ((f (x, y)) e^{(x + y)})

a - b^{9}

25 m^{2 + 10}

(- \frac{7 π}{9}) - π

What is factor (2x+3)/(4x^2-9) ?
The solution to factor (2x+3)/(4x^2-9) is 1/(2x-3)