What is factor 2ab+2cd+4ac+bd ?

The solution to factor 2ab+2cd+4ac+bd is (b+2c)(2a+d)

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factor 2ab+2cd+4ac+bd

factor

2 ab + 2 c d + 4 a c + b d

(b + 2 c) (2 a + d)

Solution steps

2 ab + 2 c d + 4 a c + b d

Factor

2 ab + 4 a c : 2 a (b + 2 c)

Factor

2 c d + b d : d (2 c + b)

= 2 a (b + 2 c) + d (2 c + b)

Factor out common term

(b + 2 c)

= (b + 2 c) (2 a + d)

(- 7 x) + (18 x^{2})

15 e^{2} + 2 e - 1

(- 56 w x^{6}) + (114 w x^{2})

10 x^{8} + y^{4 n + 4 x}

\frac{- 55 - 5 105}{8}

What is factor 2ab+2cd+4ac+bd ?
The solution to factor 2ab+2cd+4ac+bd is (b+2c)(2a+d)