What is factor 1+(x^3-2x^2) ?

The solution to factor 1+(x^3-2x^2) is (x-1)(x^2-x-1)

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factor 1+(x^3-2x^2)

factor

1 + (x^{3} - 2 x^{2})

(x - 1) (x^{2} - x - 1)

Solution steps

1 + (x^{3} - 2 x^{2})

Remove parentheses:

(a) = a

= 1 + x^{3} - 2 x^{2}

Use the rational root theorem

a_{0} = 1, a_{n} = 1

The dividers of

a_{0} : 1,

The dividers of

a_{n} : 1

Therefore, check the following rational numbers:

\pm \frac{1}{1}

\frac{1}{1}

is a root of the expression, so factor out

x - 1

= (x - 1) \frac{x ^{3} - 2 x ^{2} + 1}{x - 1}

\frac{x ^{3} - 2 x ^{2} + 1}{x - 1} = x^{2} - x - 1

= (x - 1) (x^{2} - x - 1)

x^{2} + 1 - 6 + 6

m p + m q + n p + n q

3 (sin (x))^{2} - cos (x)

(n + 1)! - 1 + (n + 1) (n + 1)!

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What is factor 1+(x^3-2x^2) ?
The solution to factor 1+(x^3-2x^2) is (x-1)(x^2-x-1)