What is (2+5i)/(2i)+(3i)/(1+4i)-1/2 ?

The solution to (2+5i)/(2i)+(3i)/(1+4i)-1/2 is (2(23-7i))/(17)

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simplify (2+5i)/(2i)+(3i)/(1+4i)-1/2

simplify

\frac{2 + 5 i}{2 i} + \frac{3 i}{1 + 4 i} - \frac{1}{2}

\frac{2 ( 23 - 7 i )}{17}

Solution steps

\frac{2 + 5 i}{2 i} + \frac{3 i}{1 + 4 i} - \frac{1}{2}

\frac{2 + 5 i}{2 i} = \frac{- 2 i + 5}{2}

\frac{3 i}{1 + 4 i} = \frac{3 i + 12}{17}

= \frac{- 2 i + 5}{2} + \frac{3 i + 12}{17} - \frac{1}{2}

Join

\frac{- 2 i + 5}{2} + \frac{3 i + 12}{17} - \frac{1}{2} : \frac{- 2 i + 4}{2} + \frac{3 i + 12}{17}

= \frac{- 2 i + 4}{2} + \frac{3 i + 12}{17}

Join

\frac{- 2 i + 4}{2} + \frac{3 i + 12}{17} : \frac{2 ( - 7 i + 23 )}{17}

= \frac{2 ( - 7 i + 23 )}{17}

Rewrite in standard complex form:

\frac{2 ( 23 - 7 i )}{17}

= \frac{2 ( 23 - 7 i )}{17}

\frac{1}{x} - 3 \geq 6

\frac{3}{4} \cdot \frac{5}{7}

- 3 x^{2} - 16 = - 3 x

(\frac{5}{4})^{\frac{3}{2}}

What is (2+5i)/(2i)+(3i)/(1+4i)-1/2 ?
The solution to (2+5i)/(2i)+(3i)/(1+4i)-1/2 is (2(23-7i))/(17)