What is the answer to a((0)^4-2(0)^2+2(0)^3+2(0)-3)=-4 ?

The answer to a((0)^4-2(0)^2+2(0)^3+2(0)-3)=-4 is a= 4/3

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a((0)^4-2(0)^2+2(0)^3+2(0)-3)=-4

a ((0)^{4} - 2 (0)^{2} + 2 (0)^{3} + 2 (0) - 3) = - 4

a = \frac{4}{3}

Solution steps

a ((0)^{4} - 2 (0)^{2} + 2 (0)^{3} + 2 (0) - 3) = - 4

Divide both sides by

- 3

a = \frac{4}{3}

(x + 5) (x^{2} - 9) (1 - x) > 0

\frac{x + 2}{x - 3} < 2

57 = 12 - 5 v

8 - 2 (z - 6) = 3 (- 3 z + 7) + 8

2 m p + 15 + 3 p + 10 m

What is the answer to a((0)^4-2(0)^2+2(0)^3+2(0)-3)=-4 ?
The answer to a((0)^4-2(0)^2+2(0)^3+2(0)-3)=-4 is a= 4/3
Solve for a: a((0)^4-2(0)^2+2(0)^3+2(0)-3)=-4
The solution is a= 4/3