What is factor 6sin^2(θ)-sin(θ)-1 ?

The solution to factor 6sin^2(θ)-sin(θ)-1 is (3sin(θ)+1)(2sin(θ)-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 6sin^2(θ)-sin(θ)-1

factor

6 sin^{2} (θ) - sin (θ) - 1

(3 sin (θ) + 1) (2 sin (θ) - 1)

Solution steps

6 sin^{2} (θ) - sin (θ) - 1

Break the expression into groups

= (6 sin^{2} (θ) + 2 sin (θ)) + (- 3 sin (θ) - 1)

Factor out

2 sin (θ)

from

6 sin^{2} (θ) + 2 sin (θ) : 2 sin (θ) (3 sin (θ) + 1)

Factor out

- 1

from

- 3 sin (θ) - 1 : - (3 sin (θ) + 1)

= 2 sin (θ) (3 sin (θ) + 1) - (3 sin (θ) + 1)

Factor out common term

3 sin (θ) + 1

= (3 sin (θ) + 1) (2 sin (θ) - 1)

tan^{2} (x) - 5 tan (x) - 6

x^{2} - \frac{20 x + 4}{25}

1 2^{2} - x - 6

a^{36} - a^{12.25}

(2^{x})^{2} - 2^{x} - 2

What is factor 6sin^2(θ)-sin(θ)-1 ?
The solution to factor 6sin^2(θ)-sin(θ)-1 is (3sin(θ)+1)(2sin(θ)-1)