What are the solutions to the equation y^2-6y+10=0 ?

The solutions to the equation y^2-6y+10=0 are y=3+i,y=3-i

Find the zeros of y^2-6y+10=0

The zeros of y^2-6y+10=0 are y=3+i,y=3-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 6 y + 10 = 0

y = 3 + i, y = 3 - i

Solution steps

y^{2} - 6 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 10 : 2 i

y_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2 i}{2 \cdot 1} : 3 + i

y = \frac{- ( - 6 ) - 2 i}{2 \cdot 1} : 3 - i

The solutions to the quadratic equation are:

y = 3 + i, y = 3 - i

x^{2} - 8 x + 2 = 0

49 r^{3} + 42 r^{2} - 42 r - 36

- \frac{10}{2}

12 x y - 9 x - 8 y + 6

5 x - 2 = 2 x + 13

What are the solutions to the equation y^2-6y+10=0 ?
The solutions to the equation y^2-6y+10=0 are y=3+i,y=3-i
Find the zeros of y^2-6y+10=0
The zeros of y^2-6y+10=0 are y=3+i,y=3-i