What is the first d/(dt)((x)(3x)) ?

The first d/(dt)((x)(3x)) is 6t

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d/(dt)((x)(3x))

\frac{d}{d t} ((t) (3 t))

6 t

Solution steps

\frac{d}{d t} ((t) (3 t))

Simplify

(t) (3 t) : 3 t^{2}

= \frac{d}{d t} (3 t^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 t^{2 - 1}

Simplify

= 6 t

\frac{d}{d x} ((f (x, y)) (x^{2} y))

e^{3} - 125

2 i z a r^{5} x^{2} + 24 x - 1485

26 + 8 \cdot 2^{\frac{3}{4}}

\frac{4}{3} x