What are the solutions to the equation 3u^2+5u=-2 ?

The solutions to the equation 3u^2+5u=-2 are u=-2/3 ,u=-1

Find the zeros of 3u^2+5u=-2

The zeros of 3u^2+5u=-2 are u=-2/3 ,u=-1

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3 u^{2} + 5 u = - 2

u = - \frac{2}{3}, u = - 1

Solution steps

3 u^{2} + 5 u = - 2

Move

2

to the left side

3 u^{2} + 5 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

5^{2} - 4 \cdot 3 \cdot 2 = 1

u_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- 5 + 1}{2 \cdot 3}, u_{2} = \frac{- 5 - 1}{2 \cdot 3}

u = \frac{- 5 + 1}{2 \cdot 3} : - \frac{2}{3}

u = \frac{- 5 - 1}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

u = - \frac{2}{3}, u = - 1

4 ∣ x - 2 ∣ + 1 = 21

x^{2} + 10 x y + 25 y^{2}

\frac{∣ 3 x + 1 ∣}{∣ x + 3 ∣} < 1

- 1 y = - 69

4. 3^{2}

What are the solutions to the equation 3u^2+5u=-2 ?
The solutions to the equation 3u^2+5u=-2 are u=-2/3 ,u=-1
Find the zeros of 3u^2+5u=-2
The zeros of 3u^2+5u=-2 are u=-2/3 ,u=-1