What are the solutions to the equation -4x^2-12x=0 ?

The solutions to the equation -4x^2-12x=0 are x=-3,x=0

Find the zeros of -4x^2-12x=0

The zeros of -4x^2-12x=0 are x=-3,x=0

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- 4 x^{2} - 12 x = 0

x = - 3, x = 0

Solution steps

- 4 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

(- 12)^{2} - 4 (- 4) \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 ( - 4 )}, x_{2} = \frac{- ( - 12 ) - 12}{2 ( - 4 )}

x = \frac{- ( - 12 ) + 12}{2 ( - 4 )} : - 3

x = \frac{- ( - 12 ) - 12}{2 ( - 4 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

2 < x \leq 5

(x - 3)^{2} = 7

6 z = 12

3 x^{2} - 9 x - 7 = 0

4 \geq x > 0

What are the solutions to the equation -4x^2-12x=0 ?
The solutions to the equation -4x^2-12x=0 are x=-3,x=0
Find the zeros of -4x^2-12x=0
The zeros of -4x^2-12x=0 are x=-3,x=0