What are the solutions to the equation 3x^2-9x-7=0 ?

The solutions to the equation 3x^2-9x-7=0 are x=(9+sqrt(165))/6 ,x=(9-sqrt(165))/6

Find the zeros of 3x^2-9x-7=0

The zeros of 3x^2-9x-7=0 are x=(9+sqrt(165))/6 ,x=(9-sqrt(165))/6

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3 x^{2} - 9 x - 7 = 0

x = \frac{9 + 165}{6}, x = \frac{9 - 165}{6}

Solution steps

3 x^{2} - 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 (- 7) = 165

x_{1, 2} = \frac{- ( - 9 ) \pm 165}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 165}{2 \cdot 3}, x_{2} = \frac{- ( - 9 ) - 165}{2 \cdot 3}

x = \frac{- ( - 9 ) + 165}{2 \cdot 3} : \frac{9 + 165}{6}

x = \frac{- ( - 9 ) - 165}{2 \cdot 3} : \frac{9 - 165}{6}

The solutions to the quadratic equation are:

x = \frac{9 + 165}{6}, x = \frac{9 - 165}{6}

4 \geq x > 0

7 x^{2} - 20 x - 3 = 0

- 4 x^{2} - 3 = 481

13 x^{2} + 1 = - 10 x

\frac{4}{3} - 1

What are the solutions to the equation 3x^2-9x-7=0 ?
The solutions to the equation 3x^2-9x-7=0 are x=(9+sqrt(165))/6 ,x=(9-sqrt(165))/6
Find the zeros of 3x^2-9x-7=0
The zeros of 3x^2-9x-7=0 are x=(9+sqrt(165))/6 ,x=(9-sqrt(165))/6