What are the solutions to the equation -4x^2-3=481 ?

The solutions to the equation -4x^2-3=481 are x=11i,x=-11i

Find the zeros of -4x^2-3=481

The zeros of -4x^2-3=481 are x=11i,x=-11i

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- 4 x^{2} - 3 = 481

x = 11 i, x = - 11 i

Solution steps

- 4 x^{2} - 3 = 481

Move

3

to the right side

- 4 x^{2} = 484

Divide both sides by

- 4

x^{2} = - 121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 121, x = - - 121

- 121 = 11 i

- - 121 = - 11 i

x = 11 i, x = - 11 i

13 x^{2} + 1 = - 10 x

\frac{4}{3} - 1

x^{6} - b^{9}

(12 m)^{\frac{1}{3}}

\frac{3}{8} + \frac{5}{6}

What are the solutions to the equation -4x^2-3=481 ?
The solutions to the equation -4x^2-3=481 are x=11i,x=-11i
Find the zeros of -4x^2-3=481
The zeros of -4x^2-3=481 are x=11i,x=-11i