What is factor f(x)(x^2-1)^{ln(x^2-1)} ?

The solution to factor f(x)(x^2-1)^{ln(x^2-1)} is fx((x+1)(x-1))^{ln((x+1)(x-1))}

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factor f(x)(x^2-1)^{ln(x^2-1)}

factor

f (x) (x^{2} - 1)^{l n (x^{2} - 1)}

f x ((x + 1) (x - 1))^{l n ((x + 1) (x - 1))}

Solution steps

f (x) (x^{2} - 1)^{l n (x^{2} - 1)}

Remove parentheses:

(a) = a

= f x (x^{2} - 1)^{l n (x^{2} - 1)}

(x^{2} - 1)^{l n (x^{2} - 1)} = ((x + 1) (x - 1))^{l n ((x + 1) (x - 1))}

= f x ((x + 1) (x - 1))^{l n ((x + 1) (x - 1))}

(- 2 X) + (3 Y)

\frac{16 x ^{4} - 81}{2 x + 3}

4 (4^{2})

ln (x^{3} - 2 x^{2} + x)

10 m x + 5 m y - 6 n x - 3 n y

What is factor f(x)(x^2-1)^{ln(x^2-1)} ?
The solution to factor f(x)(x^2-1)^{ln(x^2-1)} is fx((x+1)(x-1))^{ln((x+1)(x-1))}