What is expand (e^{2x}-4)(e^{-2x}-4) ?

The solution to expand (e^{2x}-4)(e^{-2x}-4) is -4e^{-2x}-4e^{2x}+17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{2x}-4)(e^{-2x}-4)

expand

(e^{2 x} - 4) (e^{- 2 x} - 4)

- 4 e^{- 2 x} - 4 e^{2 x} + 17

Solution steps

(e^{2 x} - 4) (e^{- 2 x} - 4)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = e^{2 x}, b = - 4, c = e^{- 2 x}, d = - 4

= e^{2 x} e^{- 2 x} + e^{2 x} (- 4) + (- 4) e^{- 2 x} + (- 4) (- 4)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= e^{2 x} e^{- 2 x} - 4 e^{2 x} - 4 e^{- 2 x} + 4 \cdot 4

Simplify

e^{2 x} e^{- 2 x} - 4 e^{2 x} - 4 e^{- 2 x} + 4 \cdot 4 : - 4 e^{- 2 x} - 4 e^{2 x} + 17

= - 4 e^{- 2 x} - 4 e^{2 x} + 17

(x + Δ x)^{2} - 4 (x + Δ x)

\frac{( x + 2 ) ( x + 5 )}{( x + 6 ) ( x + 7 )}

sin (w (t - 2))

\frac{x ( 3 x - 1 )}{( x + 1 ) ^{2}}

(4 e - 3 f)^{3}

What is expand (e^{2x}-4)(e^{-2x}-4) ?
The solution to expand (e^{2x}-4)(e^{-2x}-4) is -4e^{-2x}-4e^{2x}+17