What is expand (2x-7)/((2x-1)(3x-1)) ?

The solution to expand (2x-7)/((2x-1)(3x-1)) is (2x-7)/(6x^2-5x+1)

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expand (2x-7)/((2x-1)(3x-1))

expand

\frac{2 x - 7}{( 2 x - 1 ) ( 3 x - 1 )}

\frac{2 x - 7}{6 x ^{2} - 5 x + 1}

Solution steps

\frac{2 x - 7}{( 2 x - 1 ) ( 3 x - 1 )}

Expand

(2 x - 1) (3 x - 1) : 6 x^{2} - 5 x + 1

= \frac{2 x - 7}{6 x ^{2} - 5 x + 1}

S (1, - 4, 6)

\frac{( x - 1 ) ( x - 3 )}{3}

(5 + 2) 5 - 25

(e + 3)^{2}

(x^{3} + 3 x^{2} + 5)^{5}

What is expand (2x-7)/((2x-1)(3x-1)) ?
The solution to expand (2x-7)/((2x-1)(3x-1)) is (2x-7)/(6x^2-5x+1)