What is expand ((n^2-25)^2)/(25n^2) ?

The solution to expand ((n^2-25)^2)/(25n^2) is (n^2)/(25)-2+(25)/(n^2)

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expand ((n^2-25)^2)/(25n^2)

expand

\frac{( n ^{2} - 25 ) ^{2}}{25 n ^{2}}

\frac{n ^{2}}{25} - 2 + \frac{25}{n ^{2}}

Solution steps

\frac{( n ^{2} - 25 ) ^{2}}{25 n ^{2}}

(n^{2} - 25)^{2} = n^{4} - 50 n^{2} + 625

= \frac{n ^{4} - 50 n ^{2} + 625}{25 n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{4} - 50 n ^{2} + 625}{25 n ^{2}} = \frac{n ^{4}}{25 n ^{2}} - \frac{50 n ^{2}}{25 n ^{2}} + \frac{625}{25 n ^{2}}

= \frac{n ^{4}}{25 n ^{2}} - \frac{50 n ^{2}}{25 n ^{2}} + \frac{625}{25 n ^{2}}

Cancel

\frac{n ^{4}}{25 n ^{2}} : \frac{n ^{2}}{25}

= \frac{n ^{2}}{25} - \frac{50 n ^{2}}{25 n ^{2}} + \frac{625}{25 n ^{2}}

Cancel

\frac{50 n ^{2}}{25 n ^{2}} : 2

= \frac{n ^{2}}{25} - 2 + \frac{625}{25 n ^{2}}

Divide the numbers:

\frac{625}{25} = 25

= \frac{n ^{2}}{25} - 2 + \frac{25}{n ^{2}}

e^{(0.15 - 0.85 j)^{8}}

\frac{3 ( 1 - cos ( x ) )}{x}

(5 e^{2} - 7 f^{3}) (5 e^{2} + 7 f^{3})

\frac{( x + 2 ) ^{2}}{x + 7}

(x^{2} + 1)^{2}

What is expand ((n^2-25)^2)/(25n^2) ?
The solution to expand ((n^2-25)^2)/(25n^2) is (n^2)/(25)-2+(25)/(n^2)