What is expand 1/((x^2-9y^2)^2) ?

The solution to expand 1/((x^2-9y^2)^2) is 1/(x^4-18x^2y^2+81y^4)

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expand 1/((x^2-9y^2)^2)

expand

\frac{1}{( x ^{2} - 9 y ^{2} ) ^{2}}

\frac{1}{x ^{4} - 18 x ^{2} y ^{2} + 81 y ^{4}}

Solution steps

\frac{1}{( x ^{2} - 9 y ^{2} ) ^{2}}

(x^{2} - 9 y^{2})^{2} = x^{4} - 18 x^{2} y^{2} + 81 y^{4}

= \frac{1}{x ^{4} - 18 x ^{2} y ^{2} + 81 y ^{4}}

(- a, b, c) (- b, - a, - c)

ln (x^{2} - 36)

0.75 (x + 20 = 2 + 0.5 (x - 2))

\frac{( 3 x + 2 ) ( - 3 x + 2 )}{9}

a + b e^{a (t - t_{0})}

What is expand 1/((x^2-9y^2)^2) ?
The solution to expand 1/((x^2-9y^2)^2) is 1/(x^4-18x^2y^2+81y^4)