What is expand-((x+1)(x-3))/3 ?

The solution to expand-((x+1)(x-3))/3 is -(x^2)/3+(2x)/3+1

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expand-((x+1)(x-3))/3

expand

- \frac{( x + 1 ) ( x - 3 )}{3}

- \frac{x ^{2}}{3} + \frac{2 x}{3} + 1

Solution steps

- \frac{( x + 1 ) ( x - 3 )}{3}

Expand

(x + 1) (x - 3) : x^{2} - 2 x - 3

= - \frac{x ^{2} - 2 x - 3}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 2 x - 3}{3} = - (\frac{x ^{2}}{3}) - (- \frac{2 x}{3}) - (- \frac{3}{3})

= - (\frac{x ^{2}}{3}) - (- \frac{2 x}{3}) - (- \frac{3}{3})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{2}}{3} + \frac{2 x}{3} + \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= - \frac{x ^{2}}{3} + \frac{2 x}{3} + 1

x (x^{2} + 2 x + 3)^{2}

(3 y d x + 6 d x - x d y = 0) \frac{1}{y d x}

\frac{4}{( 4 - x ) ^{2}}

C (- 2, - 5) P (- 4, 5)

\frac{3 x + 15}{( x + 6 ) ( x + 3 )}

What is expand-((x+1)(x-3))/3 ?
The solution to expand-((x+1)(x-3))/3 is -(x^2)/3+(2x)/3+1