What is expand e^y(sinh(x)dx+cosh(x)dy=0) ?

The solution to expand e^y(sinh(x)dx+cosh(x)dy=0) is e^ysinh(x)dx+e^ycosh(x)dy=0

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expand e^y(sinh(x)dx+cosh(x)dy=0)

expand

e^{y} (sinh (x) d x + cosh (x) d y = 0)

e^{y} sinh (x) d x + e^{y} cosh (x) d y = 0

Solution steps

e^{y} (sinh (x) d x + cosh (x) d y = 0)

= e^{y} (sinh (x) d x + 0 = cosh (x) d y)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{y}, b = sinh (x) d x, c = cosh (x) d y = 0

e^{y} sinh (x) d x + e^{y} cosh (x) d y = 0

(k + 2) (k + 1)!

(x^{2} + x) e^{2 x}

e^{2 (x + i y) + i}

\frac{- 1 - 131}{6}

\frac{( x - 3 ) ( x - 4 )}{6}

What is expand e^y(sinh(x)dx+cosh(x)dy=0) ?
The solution to expand e^y(sinh(x)dx+cosh(x)dy=0) is e^ysinh(x)dx+e^ycosh(x)dy=0