What is expand pi(2ln^2(2)-2(2ln(2)-2)) ?

The solution to expand pi(2ln^2(2)-2(2ln(2)-2)) is 2piln^2(2)-4piln(2)+4pi

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expand pi(2ln^2(2)-2(2ln(2)-2))

expand

π (2 ln^{2} (2) - 2 (2 ln (2) - 2))

2 π ln^{2} (2) - 4 π ln (2) + 4 π

Solution steps

π (2 ln^{2} (2) - 2 (2 ln (2) - 2))

Apply the distributive law:

a (b - c) = ab - a c

a = π, b = 2 ln^{2} (2), c = 2 (2 ln (2) - 2)

= π 2 ln^{2} (2) - π 2 (2 ln (2) - 2)

= 2 π ln^{2} (2) - 2 π (2 ln (2) - 2)

Expand

- 2 π (2 ln (2) - 2) : - 4 π ln (2) + 4 π

= 2 π ln^{2} (2) - 4 π ln (2) + 4 π

\frac{x d x}{( x - 2 ) ( x ^{2} - 1 )}

- 3^{4}

(sin (y) - y sin (x)) d x

(1, - 2, 1) x (3, 5, - 4)

(a - 1) (a^{2} + a + 1)^{'}

What is expand pi(2ln^2(2)-2(2ln(2)-2)) ?
The solution to expand pi(2ln^2(2)-2(2ln(2)-2)) is 2piln^2(2)-4piln(2)+4pi