What is expand (a-1)(a^2+a+1)' ?

The solution to expand (a-1)(a^2+a+1)' is a(a^2+a+1)'-(a^2+a+1)'

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (a-1)(a^2+a+1)'

expand

(a - 1) (a^{2} + a + 1)^{'}

a (a^{2} + a + 1)' - (a^{2} + a + 1)'

Solution steps

(a - 1) (a^{2} + a + 1)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (a^{2} + a + 1)^{'}, b = a, c = 1

= (a^{2} + a + 1)^{^{'}} a - (a^{2} + a + 1)^{^{'}} 1

= a (a^{2} + a + 1)^{^{'}} - 1 (a^{2} + a + 1)^{^{'}}

Multiply:

1 (a^{2} + a + 1)^{'} = (a^{2} + a + 1)^{'}

= a (a^{2} + a + 1)^{^{'}} - (a^{2} + a + 1)^{^{'}}

24 x 3 y 4 - 18 x 2 y 5

\frac{3 ( 5 + 35 )}{10}

\frac{1}{( 1 - x ) ( B - x ) ( D - x )}

(e^{x} - 1) + (e^{x} - x)^{2}

4 (y + 4 = 32)

What is expand (a-1)(a^2+a+1)' ?
The solution to expand (a-1)(a^2+a+1)' is a(a^2+a+1)'-(a^2+a+1)'