What is expand ((x^2+1)(2x+3))/(3x-1) ?

The solution to expand ((x^2+1)(2x+3))/(3x-1) is (2x^3+3x^2+2x+3)/(3x-1)

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expand ((x^2+1)(2x+3))/(3x-1)

expand

\frac{( x ^{2} + 1 ) ( 2 x + 3 )}{3 x - 1}

\frac{2 x ^{3} + 3 x ^{2} + 2 x + 3}{3 x - 1}

Solution steps

\frac{( x ^{2} + 1 ) ( 2 x + 3 )}{3 x - 1}

Expand

(x^{2} + 1) (2 x + 3) : 2 x^{3} + 3 x^{2} + 2 x + 3

= \frac{2 x ^{3} + 3 x ^{2} + 2 x + 3}{3 x - 1}

(e^{t} + 2 e^{2 t})^{2}

(- 2, - 11) Y (4, 7)

\frac{2}{( 1 - x ) ( 1 + x ^{2} )}

(2 x^{2} + 3 x - 4) - (x^{2} + x = 8)

(1 - 2 x) e^{2 x}

What is expand ((x^2+1)(2x+3))/(3x-1) ?
The solution to expand ((x^2+1)(2x+3))/(3x-1) is (2x^3+3x^2+2x+3)/(3x-1)