What is expand x(x-3+1(x-3)=12) ?

The solution to expand x(x-3+1(x-3)=12) is 2x^2-6x=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand x(x-3+1(x-3)=12)

expand

x (x - 3 + 1 (x - 3) = 12)

2 x^{2} - 6 x = 12

Solution steps

x (x - 3 + 1 \cdot (x - 3) = 12)

= x (x - 3 + 1 \cdot 12 = (x - 3))

Distribute parentheses

xx + x (- 3) + x \cdot 1 \cdot (x - 3) = 12

Apply minus-plus rules

+ (- a) = - a

xx - 3 x + 1 \cdot x (x - 3) = 12

Expand

xx - 3 x + 1 \cdot x (x - 3) : 2 x^{2} - 6 x

2 x^{2} - 6 x = 12

\frac{2 ( 1 - 3 s )}{3 ( 2 s + 1 )}

\frac{6 ( a + h ) - 1}{5 ( a + h ) + 2}

(2 x^{2} + 3 x + 1)^{7}

\frac{x ( x + 1 )}{2 x - 1}

\frac{4 ( 4 ^{n + 1} - 16 )}{3}

What is expand x(x-3+1(x-3)=12) ?
The solution to expand x(x-3+1(x-3)=12) is 2x^2-6x=12