What is expand 2(3x-1)e^{2x+1} ?

The solution to expand 2(3x-1)e^{2x+1} is 6e^{2x+1}x-2e^{2x+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2(3x-1)e^{2x+1}

expand

2 (3 x - 1) e^{2 x + 1}

6 e^{2 x + 1} x - 2 e^{2 x + 1}

Solution steps

2 (3 x - 1) e^{2 x + 1}

= 2 e^{2 x + 1} (3 x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = 2 e^{2 x + 1}, b = 3 x, c = 1

= 2 e^{2 x + 1} \cdot 3 x - 2 e^{2 x + 1} \cdot 1

= 2 \cdot 3 e^{2 x + 1} x - 2 \cdot 1 \cdot e^{2 x + 1}

Simplify

2 \cdot 3 e^{2 x + 1} x - 2 \cdot 1 \cdot e^{2 x + 1} : 6 e^{2 x + 1} x - 2 e^{2 x + 1}

= 6 e^{2 x + 1} x - 2 e^{2 x + 1}

\frac{1}{( x ^{2} - 9 ) ^{3}}

u (t - π) cos (t)

5 c^{2} d e (9 c d^{2} - 7 c d + 4 e)

\frac{1}{( y ^{2} - 1 ) ( e ^{y} - 2 )}

2 (2 x - 3 y = - 19)

What is expand 2(3x-1)e^{2x+1} ?
The solution to expand 2(3x-1)e^{2x+1} is 6e^{2x+1}x-2e^{2x+1}