What is expand 1/((y^2-1)(e^y-2)) ?

The solution to expand 1/((y^2-1)(e^y-2)) is 1/(e^yy^2-2y^2-e^y+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((y^2-1)(e^y-2))

expand

\frac{1}{( y ^{2} - 1 ) ( e ^{y} - 2 )}

\frac{1}{e ^{y} y ^{2} - 2 y ^{2} - e ^{y} + 2}

Solution steps

\frac{1}{( y ^{2} - 1 ) ( e ^{y} - 2 )}

Expand

(y^{2} - 1) (e^{y} - 2) : e^{y} y^{2} - 2 y^{2} - e^{y} + 2

= \frac{1}{e ^{y} y ^{2} - 2 y ^{2} - e ^{y} + 2}

2 (2 x - 3 y = - 19)

C (3, - 5)

(x - 3) \cdot (2 x - 5 = 0)

(3 e^{x} + 1) (ln (x))

(3 x + 2 y = 18, 0) (2 x + 3 y = 50)

What is expand 1/((y^2-1)(e^y-2)) ?
The solution to expand 1/((y^2-1)(e^y-2)) is 1/(e^yy^2-2y^2-e^y+2)