What is expand (x-3)*(2x-5=0) ?

The solution to expand (x-3)*(2x-5=0) is 2x^2-5x=0

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expand (x-3)*(2x-5=0)

expand

(x - 3) \cdot (2 x - 5 = 0)

2 x^{2} - 5 x = 0

Solution steps

(x - 3) (2 x - 5 = 0)

= (x - 3) (2 x - 5 \cdot 0 =)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = x, b = - 3, c = 2 x, d = - 5 = 0

= x \cdot 2 x + x (- 5 = 0) + (- 3) \cdot 2 x + (- 3) (- 5 = 0)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

2 xx - 5 x = 0 - 3 \cdot 2 x + 3 \cdot 5 = 0

Expand

2 xx - 5 x : 2 x^{2} - 5 x

2 x^{2} - 5 x = 0

(3 e^{x} + 1) (ln (x))

(3 x + 2 y = 18, 0) (2 x + 3 y = 50)

\frac{x}{( x + 4 ) \cdot ( 2 x - 1 )}

2 (3 x + 2 y = 8)

\frac{( e ^{x} + e ^{- x} ) ^{2}}{2}

What is expand (x-3)*(2x-5=0) ?
The solution to expand (x-3)*(2x-5=0) is 2x^2-5x=0