What is expand (2-(1+k)i)/(1-ki) ?

The solution to expand (2-(1+k)i)/(1-ki) is (2-i-ki)/(1-ki)

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expand (2-(1+k)i)/(1-ki)

expand

\frac{2 - ( 1 + k ) i}{1 - ki}

\frac{2 - i - ki}{1 - ki}

Solution steps

\frac{2 - ( 1 + k ) i}{1 - ki}

Expand

2 - (1 + k) i : 2 - i - ki

= \frac{2 - i - ki}{1 - ki}

\frac{( x y ^{2} )}{z ^{4}}

\frac{1}{3 ( x ^{3} - 2 )}

8 (6 x^{3} + 4 x^{2} - x)^{3}

\frac{( x + 6 ) ( x - 1 )}{( x + 2 ) ( x - 3 )}

(x + y = 1, 5) (4 x - y = 5)

What is expand (2-(1+k)i)/(1-ki) ?
The solution to expand (2-(1+k)i)/(1-ki) is (2-i-ki)/(1-ki)