What is expand (x+y=1,5)(4x-y=5) ?

The solution to expand (x+y=1,5)(4x-y=5) is 4x^2-xy=5

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expand (x+y=1,5)(4x-y=5)

expand

(x + y = 1, 5) (4 x - y = 5)

4 x^{2} - x y = 5

Solution steps

(x + y = 1, 5) (4 x - y = 5)

= (x + 1 \cdot 5 =, y) (4 x - 5 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = x, b = y = 1, 5, c = 4 x, d = - y = 5

x \cdot 4 x + x (- y = 5) + y = 1, 5 \cdot 4 x + y = 1, 5 (- y = 5)

Apply minus-plus rules

+ (- a) = - a

4 xx - x y = 5 + y = 1, 5 \cdot 4 x - y = 1, 5 y = 5

Expand

4 xx - x y : 4 x^{2} - x y

4 x^{2} - x y = 5

(- 16 y^{2} + 144) d y

(x^{2} + y^{2}) ln (x^{2} + y^{2})

(x + y) e^{3}

\frac{( x ^{2} - x + 2 ) ( x + 3 )}{x + 1}

\frac{2 ( 4 + 2 )}{7}

What is expand (x+y=1,5)(4x-y=5) ?
The solution to expand (x+y=1,5)(4x-y=5) is 4x^2-xy=5