What is expand ((x^2-x+2)(x+3))/(x+1) ?

The solution to expand ((x^2-x+2)(x+3))/(x+1) is (x^3+2x^2-x+6)/(x+1)

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expand ((x^2-x+2)(x+3))/(x+1)

expand

\frac{( x ^{2} - x + 2 ) ( x + 3 )}{x + 1}

\frac{x ^{3} + 2 x ^{2} - x + 6}{x + 1}

Solution steps

\frac{( x ^{2} - x + 2 ) ( x + 3 )}{x + 1}

Expand

(x^{2} - x + 2) (x + 3) : x^{3} + 2 x^{2} - x + 6

= \frac{x ^{3} + 2 x ^{2} - x + 6}{x + 1}

\frac{2 ( 4 + 2 )}{7}

\frac{2 x}{( x - 5 ) ( x - 3 )}

(2 x + 3) + (2 y - 2) \frac{d y}{d x}

\frac{x - 6}{( x - 4 ) ( x + 1 )}

\frac{x ^{2} - 10 x + 2}{x ( x ^{2} - 1 )}

What is expand ((x^2-x+2)(x+3))/(x+1) ?
The solution to expand ((x^2-x+2)(x+3))/(x+1) is (x^3+2x^2-x+6)/(x+1)