What is expand e^{2t-10}h(t-5) ?

The solution to expand e^{2t-10}h(t-5) is e^{2t-10}th-5e^{2t-10}h

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expand e^{2t-10}h(t-5)

expand

e^{2 t - 10} h (t - 5)

e^{2 t - 10} t h - 5 e^{2 t - 10} h

Solution steps

e^{2 t - 10} h (t - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 t - 10} h, b = t, c = 5

= e^{2 t - 10} h t - e^{2 t - 10} h \cdot 5

= e^{2 t - 10} t h - 5 e^{2 t - 10} h

π^{e^{- 1}} - arccos (- 1)

(1 - 2) x

\frac{8 x + 71}{( x + 9 ) ( x + 8 )}

\frac{x ^{2} + x + 1}{( x + 1 ) ^{2}}

(2 x - y^{2}) d x + x y d y

What is expand e^{2t-10}h(t-5) ?
The solution to expand e^{2t-10}h(t-5) is e^{2t-10}th-5e^{2t-10}h