What is expand (((n+1)^4))/n ?

The solution to expand (((n+1)^4))/n is n^3+4n^2+6n+4+1/n

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expand (((n+1)^4))/n

expand

\frac{( ( n + 1 ) ^{4} )}{n}

n^{3} + 4 n^{2} + 6 n + 4 + \frac{1}{n}

Solution steps

\frac{( n + 1 ) ^{4}}{n}

(n + 1)^{4} = n^{4} + 4 n^{3} + 6 n^{2} + 4 n + 1

= \frac{n ^{4} + 4 n ^{3} + 6 n ^{2} + 4 n + 1}{n}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{4} + 4 n ^{3} + 6 n ^{2} + 4 n + 1}{n} = \frac{n ^{4}}{n} + \frac{4 n ^{3}}{n} + \frac{6 n ^{2}}{n} + \frac{4 n}{n} + \frac{1}{n}

= \frac{n ^{4}}{n} + \frac{4 n ^{3}}{n} + \frac{6 n ^{2}}{n} + \frac{4 n}{n} + \frac{1}{n}

\frac{n ^{4}}{n} = n^{3}

\frac{4 n ^{3}}{n} = 4 n^{2}

\frac{6 n ^{2}}{n} = 6 n

\frac{4 n}{n} = 4

= n^{3} + 4 n^{2} + 6 n + 4 + \frac{1}{n}

\frac{( x + 1 ) ( x + 2 )}{( 2 x + 1 ) ( x - 3 )}

\frac{3 x + 2}{( x ) ( x + 4 ) ^{2}}

y (4 x + y) d x - 2 (x^{2} - y) d y

d (7 cos (x) + 2 e^{x})

\frac{2 x - 16}{( x + 2 ) ( x - 2 )}

What is expand (((n+1)^4))/n ?
The solution to expand (((n+1)^4))/n is n^3+4n^2+6n+4+1/n