What is expand (x-y=5,)y(x+4y=3) ?

The solution to expand (x-y=5,)y(x+4y=3) is x^2y+4xy^2=3

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expand (x-y=5,)y(x+4y=3)

expand

(x - y = 5,) y (x + 4 y = 3)

x^{2} y + 4 x y^{2} = 3

Solution steps

(x - y = 5,) y (x + 4 y = 3)

= y (x - 5 =, y) (x + 4 \cdot 3 = y)

Expand

(x - y = 5,) (x + 4 y = 3) : x^{2} + 4 x y = 3

= y (x^{2} + 4 x y = 3)

Expand

y (x^{2} + 4 x y = 3) : x^{2} y + 4 x y^{2} = 3

x^{2} y + 4 x y^{2} = 3

(x + y) \frac{d y}{d x}

\frac{( ql + 6 p ) l}{8}

f (e^{t} - e^{- t} - 2 t)

\frac{7}{( 4 x + 1 ) ^{2}}

(x + Δ x) (x + Δ x - 4)

What is expand (x-y=5,)y(x+4y=3) ?
The solution to expand (x-y=5,)y(x+4y=3) is x^2y+4xy^2=3