What is expand (b(9-c))/(a^2) ?

The solution to expand (b(9-c))/(a^2) is (9b)/(a^2)-(bc)/(a^2)

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expand (b(9-c))/(a^2)

expand

\frac{b ( 9 - c )}{a ^{2}}

\frac{9 b}{a ^{2}} - \frac{b c}{a ^{2}}

Solution steps

\frac{b ( 9 - c )}{a ^{2}}

Expand

b (9 - c) : 9 b - b c

= \frac{9 b - b c}{a ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 b - b c}{a ^{2}} = \frac{9 b}{a ^{2}} - \frac{b c}{a ^{2}}

= \frac{9 b}{a ^{2}} - \frac{b c}{a ^{2}}

2 x^{2}

- \frac{2 ( - y ^{2} + 9 ) ^{2}}{81}

(y^{2} + 3 x) d x + e^{x} d y

4 (x + d x)^{2}

(4 m + 3) e^{3}

What is expand (b(9-c))/(a^2) ?
The solution to expand (b(9-c))/(a^2) is (9b)/(a^2)-(bc)/(a^2)