What is expand derivative of (a+be^x)+e ?

The solution to expand derivative of (a+be^x)+e is derivative of ae^x+be^x+e

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expand derivative of (a+be^x)+e

expand

\frac{d}{d x} ((a + b) e^{x}) + e

\frac{d}{d x} (a e^{x} + b e^{x}) + e

Solution steps

\frac{d}{d x} ((a + b) e^{x}) + e

Expand

(a + b) e^{x} : a e^{x} + b e^{x}

= \frac{d}{d x} (a e^{x} + b e^{x}) + e

- \frac{( x - 10 ) ^{2}}{2}

e^{\frac{1}{x - 1}} \cdot (2 x + 1)

(2 x + vx) (v d x + x d v)

(1 + ln (x)) x^{2}

e^{t - 2} cos ((a + b + c) t)

What is expand derivative of (a+be^x)+e ?
The solution to expand derivative of (a+be^x)+e is derivative of ae^x+be^x+e