What is expand (x+4)/((x-5)(x+3)) ?

The solution to expand (x+4)/((x-5)(x+3)) is (x+4)/(x^2-2x-15)

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expand (x+4)/((x-5)(x+3))

expand

\frac{x + 4}{( x - 5 ) ( x + 3 )}

\frac{x + 4}{x ^{2} - 2 x - 15}

Solution steps

\frac{x + 4}{( x - 5 ) ( x + 3 )}

Expand

(x - 5) (x + 3) : x^{2} - 2 x - 15

= \frac{x + 4}{x ^{2} - 2 x - 15}

p (1, - 3, 2) y Q (2, 1, - 1)

\frac{5 s + 13}{s ( s + 2 - 3 j )}

2 (9 n - 1) + 7 (n + 6 = - 60)

\frac{1}{( ( x + h ) - 3 ) ^{2}}

(x + x Δ)^{2}

What is expand (x+4)/((x-5)(x+3)) ?
The solution to expand (x+4)/((x-5)(x+3)) is (x+4)/(x^2-2x-15)