What is expand 1/((x+1)(3x+1)(6x+3)) ?

The solution to expand 1/((x+1)(3x+1)(6x+3)) is 1/(18x^3+33x^2+18x+3)

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expand 1/((x+1)(3x+1)(6x+3))

expand

\frac{1}{( x + 1 ) ( 3 x + 1 ) ( 6 x + 3 )}

\frac{1}{18 x ^{3} + 33 x ^{2} + 18 x + 3}

Solution steps

\frac{1}{( x + 1 ) ( 3 x + 1 ) ( 6 x + 3 )}

Expand

(x + 1) (3 x + 1) (6 x + 3) : 18 x^{3} + 33 x^{2} + 18 x + 3

= \frac{1}{18 x ^{3} + 33 x ^{2} + 18 x + 3}

\frac{8 x ^{2} + 12 x}{( 3 x - 2 ) ^{2}}

\frac{d}{d y} ((x) (x^{2} - 7))

- \frac{x ^{3} + 1}{x ( x - 1 ) ^{3}}

(x^{2} - 1) e^{x^{2}}

\frac{( n - 2 ) ( n - 1 )}{2}

What is expand 1/((x+1)(3x+1)(6x+3)) ?
The solution to expand 1/((x+1)(3x+1)(6x+3)) is 1/(18x^3+33x^2+18x+3)